Reply to "How well would you do at GCSE?"

El LoroMember VIP10 yearsModerator

Extremely Fluffy Fluffy Thing posted:
In binary if the rightmost digit is a '1' then the denary equivalent is odd, if the rightmost digit is a '0' then the denary equivalent will be even, no matter what the other digits are. There was only one even choice given, so that had to be the answer as the rightmost digit in the binary sequence given was a zero.

Exactly nod

8/28/1612:45 AM

<ul id="{%=id%}ButtonGroup" class="button-group h-popup-buttons even-button-group even-1">
    <li id="{%=id%}Okay_buttonContainer"><a id="{%=id%}Okay" href="javascript:void(0);" class="button success no-margin-bottom h-alert-modal-ok-button" role="button">OK</a><script type="text/javascript">
        (function() {
            function {%=id%}Okay_click(event, data) {
            {%=id%}Popup.hide();
        }
        
                $('#{%=id%}Okay').on('click', {%=id%}Okay_click);
        })();
    </script></li></ul><a href="javascript:void(0);" class="close-reveal-modal" aria-label="Close Modal">&#215;</a><div class="last-modal-focus focus-utility-element" tabindex="0"></div>
</div>
<script type="text/javascript">
        (function() {
            {%=id%}Popup = new SS.Popup.ModalPopup('{%=id%}');
        })();
    </script>

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